Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 6 - The Normal Distribution - Review Exercises - Section 6-2 - Page 362: 5


$0.113$ between 4869 and 5679

Work Step by Step

Given $\mu=5274, \sigma=600$ Value 6000 corresponds to $z=\frac{6000-5274}{600}=1.21$ The area to the left of z=1.21 is 0.887 The probability that a randomly selected person spends more than 6000 is $1-0.887=0.113$ Middle $50\%$ corresponds to z scores from -0.6745 to +0.6745, this gives the range of expenditures from $5274-600\times0.6745$ to $5274+600\times0.6745$ So the limits are 4869 and 5679
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