## Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

$0.113$ between 4869 and 5679
Given $\mu=5274, \sigma=600$ Value 6000 corresponds to $z=\frac{6000-5274}{600}=1.21$ The area to the left of z=1.21 is 0.887 The probability that a randomly selected person spends more than 6000 is $1-0.887=0.113$ Middle $50\%$ corresponds to z scores from -0.6745 to +0.6745, this gives the range of expenditures from $5274-600\times0.6745$ to $5274+600\times0.6745$ So the limits are 4869 and 5679