Answer
not normal
Work Step by Step
1. Construct a frequency distribution and draw a histogram for the data as shown in the figure.
We can see that the distribution is right skewed.
2. Check for skewness using the Pearson coefficient with $\bar X=481.5, median=460, s=166.9$
we have $PC=\frac{3(481.5-460)}{166.9}=0.386$ which shows a right skewed distribution.
3. Check for outliers, with $Q1=340,Q3=550,IQR=210$, we set up a range of $340-1.5IQR=25$ to
$550+1.5IQR=865$ and we can see that 1 data point (1010) is an outlier.
Because of the skewness and the outlier, we conclude that the distribution is not normal.
