Answer
$9222$ and $7290$
Work Step by Step
We have $\mu=8256,\sigma=1150$.
To appeal to the middle 60% of the market, the left tail probability would be
$P(z1)=0.5-0.6/2=0.2$ and
for the maximum $P(z2)=0.5+0.6/2=0.8$. Use Table E, we find
$z1=-0.844,z2=0.844$
The maximum $X2$ and minimum $(X2)$ prices can be found using
$z2=\frac{X2-8256}{1150}=0.84, X2=9222$ and
$z1=\frac{X1-8256}{1150}=-0.84, X1=7290$
