Answer
A and B are not mutually exclusive, because P(A and B)$\ne0$
A and B are not independent, since P(A and B)$\ne$P(A)*P(B),
P(A|B)=0.0717
P(not B)=0.721
P(A and B)=0.02
Work Step by Step
Given P(A) = 0.342, P(B) = 0.279, and P(A or B) = 0.601.
Since P(A or B)=P(A)+P(B)-P(A and B), we have 0.601=0.342+0.279-P(A and B)
which gives: P(A and B)=0.02
Are A and B mutually exclusive? No, because P(A and B)$\ne0$
Are A and B independent? No. Since P(A and B)$\ne$P(A)*P(B), A and B are not independent.
Find P(A|B), =P(A and B)/P(B)=0.02/0.279=0.0717
P(not B)=1-P(B)=0.721
P(A and B)=0.02
