#### Answer

boundary is 8.235-11.365
midpoint is 9.80
width is 3.12

#### Work Step by Step

Since the class has 2 decimal places, the boundary will have 3 decimal place. Subtract 0.005 from smallest value and add 0.005 to the largest value to find the boundary.
$8.24-0.005=8.235$
$11.36+0.005=11.365$
To find the midpoint, add the upper and lower values and divide by 2.
$\frac{8.24+11.36}{2}=\frac{19.60}{2}=9.80$
To find the width, subtract the lower value from the upper value.
$11.36-8.24=3.12$