Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 2 - Frequency Distributions and Graphs - 2-1 Organizing Data - Exercise 2-1 - Page 51: 5

Answer

boundary is 42.5-47.5 midpoint is 45 width is 4

Work Step by Step

Since the class has 0 decimal places, the boundary will have 1 decimal place. Subtract 0.5 from smallest value and add 0.5 to the largest value to find the boundary. To find the midpoint, add the upper and lower values and divide by 2. $\frac{43+47}{2}=\frac{90}{2}=45$ To find the width, subtract the lower value from the upper value. $47-43=4$
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