#### Answer

boundary is 42.5-47.5
midpoint is 45
width is 4

#### Work Step by Step

Since the class has 0 decimal places, the boundary will have 1 decimal place. Subtract 0.5 from smallest value and add 0.5 to the largest value to find the boundary.
To find the midpoint, add the upper and lower values and divide by 2.
$\frac{43+47}{2}=\frac{90}{2}=45$
To find the width, subtract the lower value from the upper value.
$47-43=4$