Answer
Step 1:
$H_0$ : The proportions of Internet users differ for any of the groups.
$H_1$: The proportions of Internet users do not differ for any of the groups.
Step 2:
Since α=0.05, and the degrees of freedom are 3-1=2 , the critical value is 5.991.
Step 3:
Expected Value:
E = n/k = 125/3 = 41.67
Test Value :
χ2 = Σ $\frac{(O-E)^{2}}{E}$ =$\frac{(40-41.67
)^{2}}{41.67}$ + $\frac{(41-41.67)^{2}}{41.67}$ + $\frac{(40-41.67^{2}}{41.67}$
=0.067+0.011+0.131 = 0.208
Step 4:
Since0.208< 5.991, the decision is not to reject the null hypothesis.
Step 5:
There is no enough evidence to reject the claim and hence we conclude that the proportions of Internet users differ for any of the groups.
