Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 11 - Other Chi-Square Tests - 11-1 Test for Goodness of Fit - Exercises 11-1 - Page 620: 12

Answer

Step 1: $H_0$ : The proportions of the services provided to low income children up to the age of 5 years and their families are as follows: 4% 5 year-olds, 52% four-year-olds, 34% three-year-olds, and 10% under 3 years. $H_1$: The distribution is not the same as stated in the null hypothesis. Step 2: Since α=0.05, and the degrees of freedom are 4-1=3 , the critical value is 7.815 Step 3: Expected Value: 0.04 * 200 = 8 0.52 * 200 = 104 0.34 * 200 =68 0.10 * 200 =20 Test Value : χ2 = Σ $\frac{(O-E)^{2}}{E}$ =$\frac{(20-8)^{2}}{8}$ + $\frac{(120-104)^{2}}{104}$ + $\frac{(40-68)^{2}}{68}$ + $\frac{(20-20)^{2}}{20}$ =18+2.4622+11.529+0 =31.991 Step 4: Since P(Χ2 > 31.991) = 0 < α, the decision is to reject the null hypothesis. Step 5: There is enough evidence to reject the claim and hence we conclude that the proportions are differ from the programs.
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