Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 11 - Other Chi-Square Tests - 11-1 Test for Goodness of Fit - Exercises 11-1 - Page 619: 7

Answer

Step 1: $H_0$ : The proportions of college students and their recent purchases are as follows: 77.8% were full-lengths CDs, 12.8% were digital downloads, 3.8% were singles, others were 5.6%. $H_1$: The distribution is not the same as stated in the null hypothesis. Step 2: Since α=0.05, and the degrees of freedom are 4-1=3 , the critical value is 7.815. Step 3: Expected Value: 0.778 * 200 = 155.6 0.128 * 200 = 25.6 0.038 * 200 = 7.6 0.056 *200 = 11.2 Test Value : χ2 = Σ $\frac{(O-E)^{2}}{E}$ =$\frac{(135-155.6)^{2}}{155.6}$ + $\frac{(48-25.6)^{2}}{25.6}$ + $\frac{(10-7.6)^{2}}{7.6}$ + $\frac{(7-11.2)^{2}}{11.2}$ =2.727+19.6+0.758+1.575 =24.660 Step 4: Since 24.660 > 7.815, the decision is to reject the null hypothesis. Step 5: There is enough evidence to reject the claim and conclude that at least one of the proportions differs from its original value.
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