Answer
p is between 0.53-0.1678=0.3622 and 0.53+0.1678=0.6978.
Work Step by Step
The best point estimate is equal to the proportion of the sample (x) divided by the sample size: $\hat{p}=\frac{x}{n}=\frac{18}{34}=0.53.$
$E=z_{\frac{\alpha}{2}}\cdot \sqrt{\frac{\hat{p}\cdot (1-\hat{p})}{n}}=1.96\cdot \sqrt{\frac{0.53\cdot (1-0.53)}{34}}=0.1678.$
Hence, the confidence interval: E is between $\hat{p}-E$ and $\hat{p}+E$, hence p is between 0.53-0.1678=0.3622 and 0.53+0.1678=0.6978.
