#### Answer

a)0.93
b)p is between 0.93-0.0162=0.9138 and 0.93+0.0162=0.9462.
c)The method is effective.

#### Work Step by Step

a) The best point estimate is equal to the proportion of the sample (x) divided by the sample size: $\hat{p}=\frac{x}{n}=\frac{879}{947}=0.93.$
b)$E=z_{\frac{\alpha}{2}}\cdot \sqrt{\frac{\hat{p}\cdot (1-\hat{p})}{n}}=2.575\cdot \sqrt{\frac{0.93\cdot (1-0.93)}{947}}=0.0162.$
Hence, the confidence interval: E is between $\hat{p}-E$ and $\hat{p}+E$, hence p is between 0.93-0.0162=0.9138 and 0.93+0.0162=0.9462.
c) The method is effective, because without the method, the proportion would be approximately 50%, whilst here, according to b), 50% is much lower than the lower bound of the confidence interval.