#### Answer

a)0.43
b)0.0162
c)p is between 0.43-0.0162=0.4138 and 0.43+0.0162=0.4462.
d)We are 90% sure that p is between 0.4138 and 0.4462.

#### Work Step by Step

a) The best point estimate is equal to the proportion of the sample (x) divided by the sample size: $\hat{p}=\frac{x}{n}=\frac{1083}{2518}=0.43.$
b)$E=z_{\frac{\alpha}{2}}\cdot \sqrt{\frac{\hat{p}\cdot (1-\hat{p})}{n}}=1.645\cdot \sqrt{\frac{0.43\cdot (1-0.43)}{2518}}=0.0162.$
c) Confidence interval: E is between $\hat{p}-E$ and $\hat{p}+E$, hence p is between 0.43-0.0162=0.4138 and 0.43+0.0162=0.4462.
d)We are 90% sure that p is between 0.4138 and 0.4462.