Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - Review - Review Exercises - Page 317: 9


$0.2296$. This is not unusually low, and the results are consistent with the hypothesis.

Work Step by Step

We find: $μ=np=(1064)(0.75)=798 $ $σ=\sqrt{npq}=\sqrt{(1064)(0.25)(0.75)}=14.12$ Hence, we find z: $z=\frac{787.5−798}{14.12}=−0.74$ Thus, using the table of z-scores, we can find that the corresponding probability is: $0.2296$. Hence we can see that the values are not unusually low. In addition, because $22.96$ percent is very possible, this means that the hypothesis is not violated.
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