Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - Review - Review Exercises - Page 317: 10

Answer

a) $0.70$ b) $0.11$

Work Step by Step

a) We find: $μ=np=(64)(0.8)=51.2 $ $σ=\sqrt{npq}=\sqrt{(64)(0.8)(0.2)}=32$ Hence, we find z: $z=\frac{49.5−51.2}{3.2}=−0.53$ Thus, using the table of z-scores, we can find that the corresponding probability is: $1−0.3=0.7$. b) We find the second z: $z=\frac{50.5−51.2}{3.2}=−0.22$ Thus, using the table of z-scores, we can find that the corresponding probability is: $0.41−0.3=0.11$.
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