## Elementary Statistics (12th Edition)

Published by Pearson

# Chapter 6 - Normal Probability Distributions - 6-7 Normal as Approximation to Binomial - Basic Skills and Concepts - Page 311: 4

#### Answer

The requirements are satisfied.

#### Work Step by Step

1 out of 5 answers is correct, hence $p=\frac{1}{5}=0.2.$ q=1-p=1-0.2=0.8 The requirements are: $n\cdot p\geq=5.$ and $n\cdot q\geq5.$ $n\cdot p=25\cdot 0.2=5\geq5.$ $n\cdot q=25\cdot 0.8=20\geq5.$ Hence, the requirements are satisfied.

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