Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - 6-7 Normal as Approximation to Binomial - Basic Skills and Concepts - Page 311: 3


p=0.2, q=0.8, $\mu=5$,$\sigma=2.$

Work Step by Step

1 out of 5 answers is correct, hence $p=\frac{1}{5}=0.2.$ q=1-p=1-0.2=0.8 mean of a binomial distribution: $\mu=n\cdotp=25\cdot0.2=5.$ standard deviation: $\sigma=\sqrt{n\cdot p\cdot q}=\sqrt{25 \cdot0.2\cdot0.8}=\sqrt4=2.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.