Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - 6-5 The Central Limit Theorem - Basic Skills and Concepts - Page 294: 16


a) $0.5239$ b) $0.8944$ c) Yes

Work Step by Step

a) We first find the value of z: $z=\frac{0.8565−0.8535}{0.0518/\sqrt1}=0.06$ Using the table of z-values, we see that the probability is $0.5239$. b) $z=\frac{0.8565−0.8535}{0.0518/\sqrt{465}}=1.25$ Using the table of $z$-values, we see that the probability is $0.8944$. c) Yes, since the rate is almost $90$ %, it seems that the claim is fair.
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