Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - 6-5 The Central Limit Theorem - Basic Skills and Concepts - Page 294: 15

Answer

a) $140$ b) $.9999$ c) $0.8078$ d)No

Work Step by Step

a)mean weight: $\frac{3500}{25}=140$ Ibs b)z-score: $z=\frac{(140)−(182.9)}{40.8/(\sqrt{25})}=−5.257$ This is less than $-3.5$, hence the probability is $0.9999$. c) z-score: $z=\frac{175−182.9}{40.8/\sqrt{20}}=−0.87$ Consulting the table of $z$-scores, we see that the probability is $0.8078$. d) No, this is still not safe. A much higher probability is required for safety regulations.
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