Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-5 Poisson Probability Distributions - Basic Skills and Concepts - Page 234: 14


a)0.136719 b)0.991 c)0.009 d)No.

Work Step by Step

a) mean=$0.000011\cdot 12429=0.136719.$ b)$P=P(X=0)+P(X=1)=\frac{0.136719^0\cdot e^{-0.136719}}{0!}+\frac{0.136719^1\cdot e^{-0.136719}}{1!}=0.872+0.119=0.991.$ c)$P(X>1)=1-P(X\leq2)=1-0.991=0.009.$ d) The probability of having more than 1 is really small, therefore the probability of having 4 is even smaller, therefore the answer is no.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.