Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-4 Parameters for Binomial Distributions - Basic Skills and Concepts: 8

Answer

Mean:6.016. Standard deviation2.373. Minimum usual value:1.27, maximum usual value:10.762.

Work Step by Step

Mean=$n\cdot p=94 \cdot 0.064=6.016$. Standard deviation: $\sqrt{n \cdot p \cdot (1-p)}=\sqrt{94 \cdot 0.064 \cdot 0.936}=2.373.$ If a value is unusual, then it is more than two standard deviations far from the mean. $Minimum \ usual \ value=mean-2\cdot(standard \ deviation)=6.016-2\cdot2.373=1.27$ $Maximum \ usual \ value=mean+2\cdot(standard \ deviation)=6.016+2\cdot2.373=10.762$.
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