Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-4 Parameters for Binomial Distributions - Basic Skills and Concepts: 7

Answer

Mean:668.58. Standard deviation:15.08. Minimum usual value:638.42, maximum usual value:698.74.

Work Step by Step

Mean=$n\cdot p=1013 \cdot 0.66=668.58$. Standard deviation: $\sqrt{n \cdot p \cdot (1-p)}=\sqrt{1013 \cdot 0.66 \cdot 0.34}=15.08.$ If a value is unusual, then it is more than two standard deviations far from the mean. $Minimum \ usual \ value=mean-2\cdot(standard \ deviation)=668.58-2\cdot15.08=638.42$ $Maximum \ usual \ value=mean+2\cdot(standard \ deviation)=668.58+2\cdot15.08=698.74$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.