Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-2 Probability Distributions - Basic Skills and Concepts - Page 208: 15

Answer

Mean:5, standard deviation:1.6.

Work Step by Step

Mean: $0\cdot0.001+1\cdot0.01+2\cdot0.044+3\cdot0.117+4\cdot0.205+5\cdot0.246+6\cdot0.205+7\cdot0.117+8\cdot0.044+9\cdot0.01+10\cdot0.001=5$. Standard deviation: $\sqrt{(0-5)^2\cdot0.001+(1-5)^2 \cdot0.01+(2-5)^2\cdot0.044+(3-5)^2\cdot0.117+(4-5)^2\cdot0.205+(5-5)^2\cdot0.246+(6-5)^2\cdot0.205+(7-5)^2\cdot0.117+(8-5)^2\cdot0.044+(9-5)^2\cdot0.01+(10-5)^2\cdot0.001}=1.6$.
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