Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 5 - Discrete Probability Distributions - 5-2 Probability Distributions - Basic Skills and Concepts - Page 208: 12


Probability distribution, mean:4.6, standard deviation:1.

Work Step by Step

It is a probability distribution because $\sum P(x)=0+0.003+0.025+0.111+0.279+0.373+0.208\approx1$. Mean :$0\cdot0+1\cdot0.003+2\cdot0.025+3\cdot0.111+4\cdot0.279+5\cdot0.373+6\cdot0.208=4.6$. Standard deviation: $\sqrt{(0-4.6)^2\cdot0+(1-4.6)^2 \cdot0.003+(2-4.6)^2\cdot0.025+(3-4.6)^2\cdot0.111+(4-4.6)^2\cdot0.279+(5-4.6)^2\cdot0.373+(6-4.6)^2\cdot0.208}=1$.
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