Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 4 - Probability - 4-3 Addition Rule - Basic Skills and Concepts: 29

Answer

$0.8797$

Work Step by Step

We know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$ and by the inclusion-exclusion principle:$P(A \cup B)=P(A)+P(B)-P(A\cap B)$. A:responded B:his/her age is between 18 and 21. By checking the data: $P(A)=\frac{1049}{1205}$ $P(B)=\frac{84}{1205}$ $P(A\cap B)=\frac{73}{1205}$ Therefore the probability of the person responding or his/her age being between 18 and 21: $P(A \cup B)=\frac{1049}{1205}+\frac{84}{1205}-\frac{73}{1205}=\frac{1060}{1205}\approx0.8797$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.