Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-1 - Sample Spaces and Events - Exercises - Page 28: 2-41

Answer

(a) 416,965,528 (b) 113,588,800 (c) 130,721,752

Work Step by Step

(a) The number of samples of size five is $\frac{140!}{5! 135!} = 416,965,528$ (b) There are 10 ways of selecting one nonconforming chip and there are $\frac{130!}{4! 126!} = 11,358,880$ ways of selecting four conforming chips. Therefore, the number of samples that contain exactly one nonconforming chip is $10 \times \frac{130!}{4! 126!} = 113,588,800$ (c) The number of samples that contain at least one nonconforming chip is the total number of samples $140C5$ minus the number of samples that contain no nonconforming chips $130C5$. Threfore, $\frac{140!}{5! 135!} - \frac{130!}{5! 125!} = 130,721,752$
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