Chapter 2 - Section 2-1 - Sample Spaces and Events - Exercises - Page 28: 2-38

3628800

Here, we need to arrange 10 different operations in any sequence, so according to permutation formula, there are $^{10}P_{10}$ ways of doing it. So, the number of possible sequences are: $^{10}P_{10}=10!=3628800$ sequences