Answer
$x+2y-7z= -6$
Work Step by Step
The formula for the equation of a plane through the point $(x_{0},y_{0},z_{0})$ and having the perpendicular vector $a\textbf{i}+b\textbf{j}+c\textbf{k}$ is
$a(x-x_{0})+b(y-y_{0})+c(z-z_{0})=0$
Therefore, the equation for the given plane is
$-1(x+2)-2(y-5)+7(z-2)=0$
or $-x-2-2y+10+7z-14=0$
or $x+2y-7z= -6$
