Answer
$2x+3y-5z= 2$
Work Step by Step
$<2,3,-5>$
$(x_{0},y_{0},z_{0})=(2,1,1)$
Equation of the plane in scalar form is
$a(x-x_{0})+b(y-y_{0})+c(z-z_{0})=0$
That is,
$2(x-2)+3(y-1)-5(z-1)=0$
or $2x-4+3y-3-5z+5= 0$
or $2x+3y-5z= 2$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 9 - Review - Exercises - Page 674: 49
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