Answer
$=\frac{\pi}{3}+2k\pi$ and $x=\frac{2\pi}{3}+2k\pi$
Work Step by Step
First find solutions in the interval $(0;2\pi)$:
$\sin x=\frac{\sqrt 3}{2}$ for $x= \frac{\pi}{3}$ and $x=\frac{2\pi}{3}$.
Next find all solutions by adding $2k\pi$:
$x=\frac{\pi}{3}+2k\pi$
$x=\frac{2\pi}{3}+2k\pi$
