Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.4 - Basic Trigonometric Equations - 7.4 Exercises - Page 569: 39

Answer

$\theta \approx 1.107+\pi k$ $\theta \approx -1.107+\pi k$ $\theta =\dfrac {2\pi }{3}+2\pi k$

Work Step by Step

$\left( \tan ^{2}\theta -4\right) \left( 2\cos \theta +1\right) =0$ 1)$ \left( \tan ^{2}\theta -4\right) =0\Rightarrow \tan \theta =\pm 2\Rightarrow \ $$\theta =\tan ^{-1}\left( 2\right) \Rightarrow \theta \approx 1.107+\pi k$ $\theta =\tan ^{-1}\left( -2\right) \Rightarrow \theta \approx -1.107+\pi k$ 2)$2\cos \theta +1=0\Rightarrow \cos \theta =-\dfrac {1}{2}\Rightarrow \theta =\dfrac {2\pi }{3}+2\pi k$
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