Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 520: 8

Answer

$$\theta \approx 111.03 ^o$$

Work Step by Step

$\theta = \angle C$ $$cos \space \theta = \frac{a^2 + b^2 - c^2}{2ab}$$ $$cos \space \theta = \frac{(122.5)^2 + (60.1)^2 - (154.6)^2}{2(122.5)(60.1)}$$ $$cos \space \theta \approx -0.358783$$ $$\theta = cos^{-1} \space - 0.358783 \approx 111.03 ^o$$
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