Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 520: 7

Answer

$$\theta = 29.89 ^o$$

Work Step by Step

$\theta = \angle B$ $$cos \space \theta = \frac{a^2 + c^2 - b^2}{2ac}$$ $$cos \space \theta = \frac{(68.01)^2 + (42.15)^2 - (37.83)^2}{2(68.01)(42.15)}$$ $$cos \space \theta \approx 0.867027$$ $$\theta = cos^{-1} \space 0.867027 = 29.89 ^o$$
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