Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.5 - The Law of Sines - 6.5 Exercises - Page 515: 36

Answer

$161.07$ft

Work Step by Step

Apply law of sines formula. $\dfrac{\sin B}{b}=\dfrac{\sin C}{c}$ or, $\sin C=\dfrac{165 \sin 67^{\circ}}{180}=0.844$ This gives: $C=57.54^{\circ}$ or, $C=122.46^{\circ}$ But, $122.46^{\circ}+67^{\circ} \gt 180^{\circ}$ , so we will have the value of $C$ is: $C=57.54^{\circ}$ Now, we have $A=180^{\circ}-B-C=55.46^{\circ}$ $\dfrac{\sin 55.46^{\circ}}{a}=\dfrac{\sin 67^{\circ}}{b}$ or, $a=\dfrac{180 \sin 67^{\circ}}{\sin 55.46^{\circ}}=161.07$ft
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