Answer
$AB \approx 56$m
Work Step by Step
Need to find the length of the tower AB.
The exterior angle at a vertex of a triangle is equal to the sum of the sizes of the interior angles at the other two vertices of the triangle.
Thus, we have $90^{\circ}+5.6^{\circ}=x+29.2^{\circ}$
$\implies x=90^{\circ}+5.6^{\circ}-29.2^{\circ}=66.4^{\circ}$
Apply law of sines formula.
$\dfrac{\sin 29.2^{\circ}}{AB}=\dfrac{\sin 66.4^{\circ}}{105}$
or, $AB=\dfrac{105 \sin 29.2^{\circ}}{\sin 66.4^{\circ}}$
This implies that $AB \approx 56$m
