Answer
(a). $\frac{8}{10}$ $i.e.$ $\frac{4}{5}$
(b). $\frac{6}{10}$ $i.e.$ $\frac{3}{5}$
(c). $\frac{8}{6}$ $i.e.$ $\frac{4}{3}$
Work Step by Step
(a). We know that-
$\sin\theta$ = $\frac{opp}{hypo}$
Therefore in given triangle, $\sin\theta$ = $\frac{8}{10}$ = $\frac{4}{5}$
Hence. $\theta$ = $\sin^{-1} \frac{8}{10}$ or $\sin^{-1} \frac{4}{5}$
(b). We know that-
$\cos\theta$ = $\frac{adj}{hypo}$
Therefore in given triangle, $\cos\theta$ = $\frac{6}{10}$ = $\frac{3}{5}$
Hence. $\theta$ = $\cos^{-1} \frac{6}{10}$ or $\cos^{-1} \frac{3}{5}$
(b). We know that-
$\tan\theta$ = $\frac{opp}{adj}$
Therefore in given triangle, $\tan\theta$ = $\frac{8}{6}$ = $\frac{4}{3}$
Hence. $\theta$ = $\tan^{-1} \frac{8}{6}$ or $\tan^{-1} \frac{4}{3}$
