Answer
$33.33 \pi$ $m^{2}$
or
104.66 $m^{2}$
Work Step by Step
Given-
Central angle of the sector. $\theta$ = $\frac{2\pi}{3}$ rad
radius, r = 10 m
A = ?
We know that area 'A' of a circular sector with central angle $\theta$ rad and radius 'r' is given by-
A = $\frac{1}{2} r^{2} \theta$
= $\frac{1}{2}\times 10^{2}\times \frac{2\pi}{3}$
= $\frac{100\pi}{3}$ square unit
= $33.33 \pi$ $m^{2}$ $\approx$ 104.66 $m^{2}$
