Answer
$θ\approx 78.58º$
Work Step by Step
All the data is given to find θ using the law of cosine:
$9^2=8^2+6^2-2(8)(6)\cdot $cos$(θ)$
$81=64+36-96\cdot $cos$(θ)$
cos$(θ)=\frac{81-64-36}{-96}$
$θ=$cos$^{-1}(\frac{-19}{-96})\approx 78.58º$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 6 - Review - Test - Page 532: 17
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