Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Test - Page 531: 6

Answer

$a=24 \sin \theta$ and $b=24 \cos \theta$

Work Step by Step

As we know that $\sin \theta=\dfrac{opposite}{hypotenuse}$ and $\cos \theta=\dfrac{adjacent}{hypotenuse}$ It can be seen from the given figure that we have $\sin \theta= \dfrac{a}{24}$ This gives: $a=24 \sin \theta$ Now, $\cos \theta=\dfrac{b}{24}$ This gives: $b=24 \cos \theta$
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