Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Section 5.2 - Trigonometric Functions of Real Numbers - 5.2 Exercises - Page 416: 4

Answer

1. $(1,0), sint=0, cost=1$ 2. $( \frac{\sqrt 3}{2}, \frac{1}{2} ), sint=\frac{1}{2}, cost=\frac{\sqrt 3}{2}$ 3. $( \frac{1}{2}, \frac{\sqrt 3}{2} ), sint=\frac{\sqrt 3}{2}, cost= \frac{1}{2}$ 4. $(0,1), sint=1, cost=0$ 5. $( - \frac{1}{2}, \frac{\sqrt 3}{2} ), sint=\frac{\sqrt 3}{2}, cost=- \frac{1}{2}$ 6. $(- \frac{\sqrt 3}{2}, \frac{1}{2} ), sint=\frac{1}{2}, cost==\frac{\sqrt 3}{2}$ 7. $(-1,0), sint=0, cost=-1$ 8. $(- \frac{\sqrt 3}{2}, -\frac{1}{2} ), sint=-\frac{1}{2}, cost==-\frac{\sqrt 3}{2}$ 9. $( - \frac{1}{2}, -\frac{\sqrt 3}{2} ), sint=-\frac{\sqrt 3}{2}, cost=- \frac{1}{2}$ 10. $(0,-1), sint=-1, cost=0$ 11. $( \frac{1}{2}, -\frac{\sqrt 3}{2} ), sint=-\frac{\sqrt 3}{2}, cost=\frac{1}{2}$ 12. $(\frac{\sqrt 3}{2}, -\frac{1}{2} ), sint=-\frac{1}{2}, cost==\frac{\sqrt 3}{2}$

Work Step by Step

Start from $(1,0)$ and go counter clockwise, there are 12 points on the unit circle, and their $(x,y), sint=y, cost=x$ can be found as the following: 1. $(1,0), sint=0, cost=1$ 2. $( \frac{\sqrt 3}{2}, \frac{1}{2} ), sint=\frac{1}{2}, cost=\frac{\sqrt 3}{2}$ 3. $( \frac{1}{2}, \frac{\sqrt 3}{2} ), sint=\frac{\sqrt 3}{2}, cost= \frac{1}{2}$ 4. $(0,1), sint=1, cost=0$ 5. $( - \frac{1}{2}, \frac{\sqrt 3}{2} ), sint=\frac{\sqrt 3}{2}, cost=- \frac{1}{2}$ 6. $(- \frac{\sqrt 3}{2}, \frac{1}{2} ), sint=\frac{1}{2}, cost==\frac{\sqrt 3}{2}$ 7. $(-1,0), sint=0, cost=-1$ 8. $(- \frac{\sqrt 3}{2}, -\frac{1}{2} ), sint=-\frac{1}{2}, cost==-\frac{\sqrt 3}{2}$ 9. $( - \frac{1}{2}, -\frac{\sqrt 3}{2} ), sint=-\frac{\sqrt 3}{2}, cost=- \frac{1}{2}$ 10. $(0,-1), sint=-1, cost=0$ 11. $( \frac{1}{2}, -\frac{\sqrt 3}{2} ), sint=-\frac{\sqrt 3}{2}, cost=\frac{1}{2}$ 12. $(\frac{\sqrt 3}{2}, -\frac{1}{2} ), sint=-\frac{1}{2}, cost==\frac{\sqrt 3}{2}$
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