Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Section 5.2 - Trigonometric Functions of Real Numbers - 5.2 Exercises - Page 416: 3

Answer

1. $(1,0), sint=0, cost=1$, 2. $(\frac{\sqrt 2}{2},\frac{\sqrt 2}{2}), sint=\frac{\sqrt 2}{2}, cost=\frac{\sqrt 2}{2}$, 3. $(0,1), sint=1, cost=0$, 4. $(-\frac{\sqrt 2}{2},\frac{\sqrt 2}{2}), sint=\frac{\sqrt 2}{2}, cost=-\frac{\sqrt 2}{2}$, 5. $(-1,0), sint=0, cost=-1$, 6. $(-\frac{\sqrt 2}{2},-\frac{\sqrt 2}{2}), sint=-\frac{\sqrt 2}{2}, cost=-\frac{\sqrt 2}{2}$, 7. $(0,-1), sint=-1, cost=0$, 8. $(\frac{\sqrt 2}{2},-\frac{\sqrt 2}{2}), sint=-\frac{\sqrt 2}{2}, cost=\frac{\sqrt 2}{2}$,

Work Step by Step

Start from $(1,0)$ and go counter clockwise, there are 8 points on unit circle, and their $(x,y)$ values, $sint=y, cost=x$ can be found as the following: 1. $(1,0), sint=0, cost=1$, 2. $(\frac{\sqrt 2}{2},\frac{\sqrt 2}{2}), sint=\frac{\sqrt 2}{2}, cost=\frac{\sqrt 2}{2}$, 3. $(0,1), sint=1, cost=0$, 4. $(-\frac{\sqrt 2}{2},\frac{\sqrt 2}{2}), sint=\frac{\sqrt 2}{2}, cost=-\frac{\sqrt 2}{2}$, 5. $(-1,0), sint=0, cost=-1$, 6. $(-\frac{\sqrt 2}{2},-\frac{\sqrt 2}{2}), sint=-\frac{\sqrt 2}{2}, cost=-\frac{\sqrt 2}{2}$, 7. $(0,-1), sint=-1, cost=0$, 8. $(\frac{\sqrt 2}{2},-\frac{\sqrt 2}{2}), sint=-\frac{\sqrt 2}{2}, cost=\frac{\sqrt 2}{2}$,
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