Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Review - Exercises - Page 464: 39

Answer

$y=\frac{1}{2}$sin$(2\pi(x+\frac{1}{3}))$

Work Step by Step

The amplitude is half the distance between the minimum and maximum values of the function. Since the minimum is $-1/2$ and the maximum is $1/2$, $\frac{1/2-(-1/2)}{2}=1/2$ The period is the interval needed to complete one cycle, and it is given by $k=\frac{2\pi}{p}$, where $p$ is the period and $k$ is the horizontal length of a function when it completes one cycle. Since the length, in this case, is 1, $k=\frac{2\pi}{1}=2\pi$ Horizontal shift is the amount of units the function has displaced horizontally. Since the sine function starts at the origin, the function has displaced $-1/3$
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