Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Review - Exercises - Page 464: 38

Answer

$y=2 \sin (\dfrac{\pi}{2})x$

Work Step by Step

As we can see from the given picture that the point$(1,2)$ is maximum, so the amplitude is $A=2$. Thus, the time period $P$ will be: $P=4$ or, $\dfrac{2\pi}{k}=4$ This gives : $k=\dfrac{\pi}{2}$ But there is no horizontal shift, this means that $B=0$ Hence, our function is: $y=2 \sin (\dfrac{\pi}{2})x$
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