Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.6 - Modeling with Exponential Functions - 4.6 Exercises - Page 379: 13

Answer

(a) $n(t)=8600e^{0.1508t}$ (b) $11627$ (c) $4.6$ hours

Work Step by Step

(a) Using an exponential model $n(t)=n_0e^{rt}$, given $n_0=8600, n(1)=10000$, we have $10000=8600e^r$, thus we can find $r=ln(100/86)=0.1508$ so we can rewrite the function as $n(t)=8600e^{0.1508t}$ (b) Let $t=2$, we have $n(2)=8600e^{0.1508\times2}\approx11627$ (c) Let $n(t)=2n_0$, we have $2n_0=n_0e^{0.1508t}$ which gives $t=ln2/0.1508\approx4.6$ hours
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