Answer
between 1 and 2,
between $2$ and $3$
Work Step by Step
$9^{1}=9$
$9^{2}=81$
$9^{3}=729 ...$
etc.
Since 20 is between 9 and 81,
$9^{1}<9^{x}<9^{2}$
x will be between 1 and 2
$100$ is between $81$ and $729$,
$9^{2}<9^{x}<9^{3}$
x will be between $2$ and $3$
