Answer
$t \in (\frac{3}{2},\infty)$
$x \in(-\infty,-1) \cup (1,\infty)$
Work Step by Step
Argument of a logarithm must be greater than 0:
a) $2t-3\gt 0$
After solving the inequality we get the result $t \in (\frac{3}{2},\infty)$
b)$x^{2}-1\gt0$
After solving the inequality we get the result $x \in(-\infty,-1) \cup (1,\infty)$
