Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Test - Page 391: 10

Answer

(a) $n(t)=1000e^{2.07944t}$ (b) $22627$ (c) $1.3$ (d) see graph below.

Work Step by Step

(a) Given $n_0=1000, n(1)=8000$ we have $1000e^r=8000$ which gives $r=2.07944$ Thus, the function can be written as $n(t)=1000e^{2.07944t}$ (b) At $t=1.5$, $n(1.5)=1000e^{2.07944\times1.5}\approx22627$ (c) Let $n(t)=1000e^{2.07944t}=15000$, we can solve $t$ which gives $t=ln(15)/2.07944\approx1.3$ (d) The above function can be graphed as shown in the figure.
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