Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises - Page 388: 1

Answer

$f(-1.5) \approx 0.089$ $f(\sqrt 2) \approx 9.739$ $f(2.5) \approx 55.902$

Work Step by Step

$Use$ $a$ $calculator$ $to$ $find$ $the$ $indicated$ $values$ $of$ $the$ $exponential$ $function,$ $rounded$ $to$ $three$ $decimal$ $places:$ $f(x) = 5^x; f(-1.5), f(\sqrt 2), f(2.5)$ a.) $f(x) = 5^x; f(-1.5)$ Plug in -1.5 for x $$f(-1.5) = 5^{-1.5}$$ Use a calculator to evaluate $$f(-1.5) = 0.0894427190999916$$ Round to 3 decimal places $$f(-1.5) \approx 0.089$$ b.)$f(x) = 5^x; f(\sqrt2)$ Plug in $\sqrt 2$ for x $$f(\sqrt 2) = 5^{\sqrt2}$$ Use a calculator to evaluate $$f(\sqrt 2) = 9.7385177423354203$$ Round to 3 decimal places $$f(\sqrt 2) \approx 9.739$$ c.)$f(x) = 5^x; f(2.5)$ Plug in 2.5 for x $$f(2.5) = 5^{2.5}$$ Use a calculator to evaluate $$f(2.5) = 55.9016994374947424$$ Round to 3 decimal places $$f(2.5) \approx 55.902$$
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