Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Review - Exercises - Page 322: 96

Answer

$(-∞, -2) U (-1, 1) U (2, ∞) $

Work Step by Step

$x^8 - 17x^4 + 16 > 0$ Find the zeros of the expression. $(x^4 - 16) (x^4 - 1)$ $(x^2 - 4) (x^2 + 4) (x^2 - 1) (x^2 + 1)$ $(x+2)(x+1)(x-1)(x-2)(x^2 + 4)(x^2 + 1)$ $x = -2, -1, 1, 2$ Test numbers in between those zero values to determine if the function is negative or positive (-∞, -2) $(-)(-)(-)(-)(+)(+) = (+)$ (-2, -1) $(+)(-)(-)(-)(+)(+) = (-)$ (-1, 1) $(+)(+)(-)(-)(+)(+) = (+)$ (1, 2) $(+)(+)(+)(-)(+)(+) = (-)$ (2, ∞) $(+)(+)(+)(+)(+)(+) = (+)$ Thus the solution is $(-∞, -2) U (-1, 1) U (2, ∞) $
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