Answer
$(-∞, -1] U [3/2, ∞) $
Work Step by Step
$2x^2 \geq x + 3$
$2x^2 - x - 3 \geq 0$
Find the zeros of the expression.
$(2x - 3)(x +1)$
$x = -1, 3/2$
Test numbers in between those zero values to determine if the function is negative or positive
(-∞, -1] $(-)(-) = (+)$
[-1, 3/2] $(-)(+) = (-)$
[3/2, ∞) $(+)(+)= (+)$
Thus the solution is $(-∞, -1] U [3/2, ∞) $
