Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.8 - One-to-One Functions and Their Inverses - 2.8 Exercises - Page 227: 93

Answer

(a) $f(n)=1.5n+16$ (b) $f^{-1}(n)=\frac{2n-32}{3}$ $f^{-1}(n)$ represents number of toppings for given $n$ amount of money. (c) The pizza has $6$ toppings.

Work Step by Step

(a) So, we have function $f$ representing the price of pizza and $n$ (variable) for amount of toppings. In addition we know that for any amount of topping we have unchangeable $16\$$ (constant) and $1.5\$$ for each topping. According to the information provided, we can simply write: $f(n)=1.5n+16$ (b) To find the inverse of the function $f$ we will follow the next steps: First write the function in terms of $y$ and $n$ (In our case $n$ stands for the $x$ we have in general cases): $y=1.5n+16$ Then replace $y$ by $n$ and vice versa: $n=1.5y+16$ And at last solve for $y$: $1.5y=n-16$ $y=\frac{n-16}{1.5}$ $y=\frac{2(n-16)}{3}$ $y=\frac{2n-32}{3}$ $f^{-1}(n)=\frac{2n-32}{3}$ $f^{-1}(n)$ represents number of toppings for given $n$ amount of money. Which is also clear, due to the definition of an inverse function; we replace $y$ (amount of money) by $n$ (number of toppings) (c) If pizza costs $\$25$, it means $f(n)=25$ $25=1.5n+16$ $1.5n=9$ $n=6$ It has $6$ toppings.
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